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Consider a circuit containing a set of elements in parallel, where each element consists of a voltage source and resistor in series We can replace such a circuit with a single voltage source and resistor in series by using Millman s theorem This theorem is actually simple to apply We just use the following steps: 1 Replace each voltage source Vi by an equivalent current source given by Ii = G i Vi , where G i = 1/Ri is the conductance of the resistor in series with the voltage source Vi 2 Compute the sum G i Vi = GV = I to obtain a single current source Sum up the conductances to obtain a single resistor in parallel with this current source 3 Invert to obtain a single voltage source and resistor that are in series The Millman voltage is VM = The Millman resistance is RM = 1 G1 + G2 + + Gn (43) G 1 V1 + G 2 V2 + + G n Vn G1 + G2 + + Gn (42) abonamente cablu si internet upc UPC Magyarország - Wikipedia
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Viteze de până la 500 Mbps, conexiune stabilă și super acoperire wifi oriunde în casă cu ... Cel mai puternic internet wifi de la UPC; + SPORT GO și HBO GO ... Consider a selection operation on a relation whose tuples are stored together in one le Two scan algorithms to implement the selection operation are: A1 (linear search) In a linear search, the system scans each le block and tests all records to see whether they satisfy the selection condition For a selection on a key attribute, the system can terminate the scan if the required record is found, without looking at the other records of the relation The cost of linear search, in terms of number of I/O operations, is br , where br denotes the number of blocks in the le Selections on key attributes have an average cost of br /2, but still have a worst-case cost of br Although it may be slower than other algorithms for implementing selection, the linear search algorithm can be applied to any le, regardless of the ordering of the le, or the availability of indices, or the nature of the selection operation The other algorithms that we shall study are not applicable in all cases, but when applicable they are generally faster than linear search A2 (binary search) If the le is ordered on an attribute, and the selection condition is an equality comparison on the attribute, we can use a binary search to locate records that satisfy the selection The system performs the binary search on the blocks of the le The number of blocks that need to be examined to nd a block containing the required records is log2 (br ) , where br denotes the number of blocks in the le If the selection is on a nonkey attribute, more than one block may contain required records, and the cost of reading the extra blocks has to be added to the cost estimate We can estimate this number by estimating the size of the selection result (which we cover in Section 142), and dividing it by the average number of records that are stored per block of the relation. EXAMPLE 4-3 Consider the circuit shown in Fig 4-7 and replace it by its Millman equivalent SOLUTION First we replace the two voltage sources by equivalent current sources In the rst case consider the 5 V source The conductance is found by inverting the resistance in series with the 5 V source, that is G1 = 1 3 The McGraw Hill Companies, 2001 upc czech internet Dostupnost Tišnov - Novinky a všeobecná diskuze - UPC Zone ...
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